Integrand size = 27, antiderivative size = 135 \[ \int (a+a \cos (c+d x))^{2/3} \left (A+C \cos ^2(c+d x)\right ) \, dx=-\frac {9 C (a+a \cos (c+d x))^{2/3} \sin (c+d x)}{40 d}+\frac {3 C (a+a \cos (c+d x))^{5/3} \sin (c+d x)}{8 a d}+\frac {(40 A+19 C) (a+a \cos (c+d x))^{2/3} \operatorname {Hypergeometric2F1}\left (-\frac {1}{6},\frac {1}{2},\frac {3}{2},\frac {1}{2} (1-\cos (c+d x))\right ) \sin (c+d x)}{10\ 2^{5/6} d (1+\cos (c+d x))^{7/6}} \]
-9/40*C*(a+a*cos(d*x+c))^(2/3)*sin(d*x+c)/d+3/8*C*(a+a*cos(d*x+c))^(5/3)*s in(d*x+c)/a/d+1/20*(40*A+19*C)*(a+a*cos(d*x+c))^(2/3)*hypergeom([-1/6, 1/2 ],[3/2],1/2-1/2*cos(d*x+c))*sin(d*x+c)*2^(1/6)/d/(1+cos(d*x+c))^(7/6)
Time = 0.80 (sec) , antiderivative size = 175, normalized size of antiderivative = 1.30 \[ \int (a+a \cos (c+d x))^{2/3} \left (A+C \cos ^2(c+d x)\right ) \, dx=\frac {(a (1+\cos (c+d x)))^{2/3} \sec ^2\left (\frac {1}{2} (c+d x)\right ) \left (6\ 2^{5/6} (40 A+28 C+14 C \cos (c+d x)+5 C \cos (2 (c+d x))) \sqrt [6]{1-\cos \left (d x-2 \arctan \left (\cot \left (\frac {c}{2}\right )\right )\right )} \sin (c+d x)-4 (40 A+19 C) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {5}{6},\frac {3}{2},\cos ^2\left (\frac {d x}{2}-\arctan \left (\cot \left (\frac {c}{2}\right )\right )\right )\right ) \sin \left (d x-2 \arctan \left (\cot \left (\frac {c}{2}\right )\right )\right )\right )}{320\ 2^{5/6} d \sqrt [6]{1-\cos \left (d x-2 \arctan \left (\cot \left (\frac {c}{2}\right )\right )\right )}} \]
((a*(1 + Cos[c + d*x]))^(2/3)*Sec[(c + d*x)/2]^2*(6*2^(5/6)*(40*A + 28*C + 14*C*Cos[c + d*x] + 5*C*Cos[2*(c + d*x)])*(1 - Cos[d*x - 2*ArcTan[Cot[c/2 ]]])^(1/6)*Sin[c + d*x] - 4*(40*A + 19*C)*Hypergeometric2F1[1/2, 5/6, 3/2, Cos[(d*x)/2 - ArcTan[Cot[c/2]]]^2]*Sin[d*x - 2*ArcTan[Cot[c/2]]]))/(320*2 ^(5/6)*d*(1 - Cos[d*x - 2*ArcTan[Cot[c/2]]])^(1/6))
Time = 0.61 (sec) , antiderivative size = 145, normalized size of antiderivative = 1.07, number of steps used = 9, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {3042, 3503, 27, 3042, 3230, 3042, 3131, 3042, 3130}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int (a \cos (c+d x)+a)^{2/3} \left (A+C \cos ^2(c+d x)\right ) \, dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int \left (a \sin \left (c+d x+\frac {\pi }{2}\right )+a\right )^{2/3} \left (A+C \sin \left (c+d x+\frac {\pi }{2}\right )^2\right )dx\) |
| \(\Big \downarrow \) 3503 |
| \(\displaystyle \frac {3 \int \frac {1}{3} (\cos (c+d x) a+a)^{2/3} (a (8 A+5 C)-3 a C \cos (c+d x))dx}{8 a}+\frac {3 C \sin (c+d x) (a \cos (c+d x)+a)^{5/3}}{8 a d}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle \frac {\int (\cos (c+d x) a+a)^{2/3} (a (8 A+5 C)-3 a C \cos (c+d x))dx}{8 a}+\frac {3 C \sin (c+d x) (a \cos (c+d x)+a)^{5/3}}{8 a d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\int \left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^{2/3} \left (a (8 A+5 C)-3 a C \sin \left (c+d x+\frac {\pi }{2}\right )\right )dx}{8 a}+\frac {3 C \sin (c+d x) (a \cos (c+d x)+a)^{5/3}}{8 a d}\) |
| \(\Big \downarrow \) 3230 |
| \(\displaystyle \frac {\frac {1}{5} a (40 A+19 C) \int (\cos (c+d x) a+a)^{2/3}dx-\frac {9 a C \sin (c+d x) (a \cos (c+d x)+a)^{2/3}}{5 d}}{8 a}+\frac {3 C \sin (c+d x) (a \cos (c+d x)+a)^{5/3}}{8 a d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {1}{5} a (40 A+19 C) \int \left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^{2/3}dx-\frac {9 a C \sin (c+d x) (a \cos (c+d x)+a)^{2/3}}{5 d}}{8 a}+\frac {3 C \sin (c+d x) (a \cos (c+d x)+a)^{5/3}}{8 a d}\) |
| \(\Big \downarrow \) 3131 |
| \(\displaystyle \frac {\frac {a (40 A+19 C) (a \cos (c+d x)+a)^{2/3} \int (\cos (c+d x)+1)^{2/3}dx}{5 (\cos (c+d x)+1)^{2/3}}-\frac {9 a C \sin (c+d x) (a \cos (c+d x)+a)^{2/3}}{5 d}}{8 a}+\frac {3 C \sin (c+d x) (a \cos (c+d x)+a)^{5/3}}{8 a d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {a (40 A+19 C) (a \cos (c+d x)+a)^{2/3} \int \left (\sin \left (c+d x+\frac {\pi }{2}\right )+1\right )^{2/3}dx}{5 (\cos (c+d x)+1)^{2/3}}-\frac {9 a C \sin (c+d x) (a \cos (c+d x)+a)^{2/3}}{5 d}}{8 a}+\frac {3 C \sin (c+d x) (a \cos (c+d x)+a)^{5/3}}{8 a d}\) |
| \(\Big \downarrow \) 3130 |
| \(\displaystyle \frac {\frac {2 \sqrt [6]{2} a (40 A+19 C) \sin (c+d x) (a \cos (c+d x)+a)^{2/3} \operatorname {Hypergeometric2F1}\left (-\frac {1}{6},\frac {1}{2},\frac {3}{2},\frac {1}{2} (1-\cos (c+d x))\right )}{5 d (\cos (c+d x)+1)^{7/6}}-\frac {9 a C \sin (c+d x) (a \cos (c+d x)+a)^{2/3}}{5 d}}{8 a}+\frac {3 C \sin (c+d x) (a \cos (c+d x)+a)^{5/3}}{8 a d}\) |
(3*C*(a + a*Cos[c + d*x])^(5/3)*Sin[c + d*x])/(8*a*d) + ((-9*a*C*(a + a*Co s[c + d*x])^(2/3)*Sin[c + d*x])/(5*d) + (2*2^(1/6)*a*(40*A + 19*C)*(a + a* Cos[c + d*x])^(2/3)*Hypergeometric2F1[-1/6, 1/2, 3/2, (1 - Cos[c + d*x])/2 ]*Sin[c + d*x])/(5*d*(1 + Cos[c + d*x])^(7/6)))/(8*a)
3.2.99.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(-2^(n + 1/2))*a^(n - 1/2)*b*(Cos[c + d*x]/(d*Sqrt[a + b*Sin[c + d*x]]))*Hypergeome tric2F1[1/2, 1/2 - n, 3/2, (1/2)*(1 - b*(Sin[c + d*x]/a))], x] /; FreeQ[{a, b, c, d, n}, x] && EqQ[a^2 - b^2, 0] && !IntegerQ[2*n] && GtQ[a, 0]
Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[a^IntPar t[n]*((a + b*Sin[c + d*x])^FracPart[n]/(1 + (b/a)*Sin[c + d*x])^FracPart[n] ) Int[(1 + (b/a)*Sin[c + d*x])^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && EqQ[a^2 - b^2, 0] && !IntegerQ[2*n] && !GtQ[a, 0]
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[(-d)*Cos[e + f*x]*((a + b*Sin[e + f*x])^m/( f*(m + 1))), x] + Simp[(a*d*m + b*c*(m + 1))/(b*(m + 1)) Int[(a + b*Sin[e + f*x])^m, x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] && !LtQ[m, -2^(-1)]
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-C)*Cos[e + f*x]*((a + b*Sin[e + f*x])^ (m + 1)/(b*f*(m + 2))), x] + Simp[1/(b*(m + 2)) Int[(a + b*Sin[e + f*x])^ m*Simp[A*b*(m + 2) + b*C*(m + 1) - a*C*Sin[e + f*x], x], x], x] /; FreeQ[{a , b, e, f, A, C, m}, x] && !LtQ[m, -1]
\[\int \left (a +\cos \left (d x +c \right ) a \right )^{\frac {2}{3}} \left (A +C \left (\cos ^{2}\left (d x +c \right )\right )\right )d x\]
\[ \int (a+a \cos (c+d x))^{2/3} \left (A+C \cos ^2(c+d x)\right ) \, dx=\int { {\left (C \cos \left (d x + c\right )^{2} + A\right )} {\left (a \cos \left (d x + c\right ) + a\right )}^{\frac {2}{3}} \,d x } \]
Timed out. \[ \int (a+a \cos (c+d x))^{2/3} \left (A+C \cos ^2(c+d x)\right ) \, dx=\text {Timed out} \]
\[ \int (a+a \cos (c+d x))^{2/3} \left (A+C \cos ^2(c+d x)\right ) \, dx=\int { {\left (C \cos \left (d x + c\right )^{2} + A\right )} {\left (a \cos \left (d x + c\right ) + a\right )}^{\frac {2}{3}} \,d x } \]
\[ \int (a+a \cos (c+d x))^{2/3} \left (A+C \cos ^2(c+d x)\right ) \, dx=\int { {\left (C \cos \left (d x + c\right )^{2} + A\right )} {\left (a \cos \left (d x + c\right ) + a\right )}^{\frac {2}{3}} \,d x } \]
Timed out. \[ \int (a+a \cos (c+d x))^{2/3} \left (A+C \cos ^2(c+d x)\right ) \, dx=\int \left (C\,{\cos \left (c+d\,x\right )}^2+A\right )\,{\left (a+a\,\cos \left (c+d\,x\right )\right )}^{2/3} \,d x \]